{"id":11082,"date":"2022-10-13T11:14:01","date_gmt":"2022-10-13T08:14:01","guid":{"rendered":"https:\/\/bestessayhomework.com\/tr\/?p=11082"},"modified":"2022-10-13T11:14:01","modified_gmt":"2022-10-13T08:14:01","slug":"dogrusal-programlama-muhasebe-alaninda-tez-yaptirma-muhasebe-tez-yaptirma-ucretleri-muhasebe-odevleri-muhasebe-odev-ucretleri","status":"publish","type":"post","link":"https:\/\/bestessayhomework.com\/tr\/dogrusal-programlama-muhasebe-alaninda-tez-yaptirma-muhasebe-tez-yaptirma-ucretleri-muhasebe-odevleri-muhasebe-odev-ucretleri\/","title":{"rendered":"Do\u011frusal Programlama \u2013 Muhasebe Alan\u0131nda Tez Yapt\u0131rma \u2013 Muhasebe Tez Yapt\u0131rma \u00dccretleri \u2013 Muhasebe \u00d6devleri \u2013 Muhasebe \u00d6dev \u00dccretleri"},"content":{"rendered":"

Bir Ba\u011flay\u0131c\u0131 \u0130\u00e7 K\u0131s\u0131tlama<\/span><\/strong><\/h3>\n

Her par\u00e7an\u0131n \u00f6zel bir makine taraf\u0131ndan delinmesi gerekti\u011fini varsay\u0131n. Firma, birlikte haftada 120 saat delme sa\u011flayan \u00fc\u00e7 makineye sahiptir. B\u00f6l\u00fcm X, bir saatlik sondaj gerektirir ve B\u00f6l\u00fcm Y, \u00fc\u00e7 saatlik sondaj gerektirir. Ba\u015fka ba\u011flay\u0131c\u0131 k\u0131s\u0131tlamalar olmad\u0131\u011f\u0131 varsay\u0131ld\u0131\u011f\u0131nda, par\u00e7alar\u0131n optimal kar\u0131\u015f\u0131m\u0131 nedir? X B\u00f6l\u00fcm\u00fc’n\u00fcn her birimi bir saat sondaj gerektirdi\u011finden, haftada 120 birim X B\u00f6l\u00fcm\u00fc \u00fcretilebilir (120\/1).<\/span><\/p>\n

Birim ba\u015f\u0131na 300 ABD Dolar\u0131 ile Schaller, haftada toplam 36.000 ABD Dolar\u0131 katk\u0131 pay\u0131 kazanabilir. \u00d6te yandan K\u0131s\u0131m Y, birim ba\u015f\u0131na \u00fc\u00e7 saat delme gerektirir; bu nedenle k\u0131rk (120\/3) par\u00e7a \u00fcretilebilir. Birim ba\u015f\u0131na 600$’da, toplam katk\u0131 marj\u0131 haftada 24.000$’d\u0131r. Yaln\u0131zca B\u00f6l\u00fcm X’i \u00fcretmek, yaln\u0131zca B\u00f6l\u00fcm Y’yi \u00fcretmekten daha y\u00fcksek bir k\u00e2r d\u00fczeyi sa\u011flar.<\/span><\/p>\n

Her bir \u00fcr\u00fcn\u00fcn birim ba\u015f\u0131na katk\u0131 pay\u0131 kritik kayg\u0131 de\u011fildir. K\u0131t kaynak birimi ba\u015f\u0131na katk\u0131 pay\u0131 belirleyici fakt\u00f6rd\u00fcr. Sondaj saati ba\u015f\u0131na en y\u00fcksek katk\u0131 pay\u0131n\u0131 veren \u00fcr\u00fcn se\u00e7ilmelidir. K\u0131s\u0131m X, makine saati ba\u015f\u0131na 300 $ (300 $\/1) kazan\u0131rken, K\u0131s\u0131m Y, makine saati ba\u015f\u0131na yaln\u0131zca 200 $ (600\/3 $) kazan\u0131r. Bu nedenle, en uygun kar\u0131\u015f\u0131m 120 birim X B\u00f6l\u00fcm\u00fc ve Y B\u00f6l\u00fcm\u00fc’n\u00fcn hi\u00e7biri de\u011fildir ve toplam katk\u0131 pay\u0131 haftada 36.000$’d\u0131r.<\/span><\/p>\n

Dahili Ba\u011flama K\u0131s\u0131tlamas\u0131 ve D\u0131\u015f Ba\u011flama K\u0131s\u0131tlamas\u0131<\/span><\/strong><\/h3>\n

K\u0131t kayna\u011f\u0131n birimi ba\u015f\u0131na katk\u0131 pay\u0131, ba\u011flay\u0131c\u0131 bir d\u0131\u015f k\u0131s\u0131tlama oldu\u011funda en uygun \u00fcr\u00fcn kar\u0131\u015f\u0131m\u0131n\u0131 belirlemek i\u00e7in de kullan\u0131labilir. \u00d6rne\u011fin, 120 sondaj saatinin ayn\u0131 dahili k\u0131s\u0131tlamas\u0131n\u0131 varsayal\u0131m, ancak ayn\u0131 zamanda Schaller’in en fazla 60 birim X B\u00f6l\u00fcm\u00fc ve 100 birim Y B\u00f6l\u00fcm\u00fc satabilece\u011fini varsayal\u0131m.<\/span><\/p>\n

Dahili k\u0131s\u0131tlama, Schaller’in 120 birim X B\u00f6l\u00fcm\u00fc \u00fcretmesine izin verir, ancak bu art\u0131k uygun bir se\u00e7im de\u011fildir, \u00e7\u00fcnk\u00fc yaln\u0131zca 60 birim X sat\u0131labilir. Bu nedenle, art\u0131k yaln\u0131zca K\u0131s\u0131m X’i \u00fcretme ve satma konusundaki \u00f6nceki karar\u0131 etkileyen ba\u011flay\u0131c\u0131 bir d\u0131\u015f k\u0131s\u0131tlamaya sahibiz.<\/span><\/p>\n

K\u0131t kaynak birimi (makine saati) ba\u015f\u0131na katk\u0131, B\u00f6l\u00fcm X i\u00e7in 300 $ ve K\u0131s\u0131m Y i\u00e7in 200 $ oldu\u011fundan, B\u00f6l\u00fcm Y’den herhangi birini \u00fcretmeden \u00f6nce B\u00f6l\u00fcm X’ten m\u00fcmk\u00fcn oldu\u011funca fazla \u00fcretmek hala mant\u0131kl\u0131d\u0131r. Schaller \u00f6nce 60 birim \u00fcretmelidir. B\u00f6l\u00fcm X, 60 makine saati kullanarak. Bu, 60 makine saati b\u0131rak\u0131r ve 20 birim Y B\u00f6l\u00fcm\u00fc \u00fcretimine olanak tan\u0131r. En uygun kar\u0131\u015f\u0131m \u015fu anda 60 birim B\u00f6l\u00fcm X ve 20 birim Y B\u00f6l\u00fcm\u00fcd\u00fcr ve haftada toplam 30.000 ABD Dolar\u0131 katk\u0131 pay\u0131 \u00fcretir.<\/span><\/p>\n

\u00c7oklu Dahili Ba\u011flama K\u0131s\u0131tlamalar\u0131<\/span><\/strong><\/h3>\n

Bir organizasyonun birden fazla ba\u011flay\u0131c\u0131 k\u0131s\u0131tlamaya sahip olmas\u0131 m\u00fcmk\u00fcnd\u00fcr. T\u00fcm organizasyonlar birden fazla k\u0131s\u0131tlamayla kar\u015f\u0131 kar\u015f\u0131yad\u0131r: malzeme s\u0131n\u0131rlamalar\u0131, i\u015fg\u00fcc\u00fc girdilerinin s\u0131n\u0131rlamalar\u0131, s\u0131n\u0131rl\u0131 makine saatleri vb. \u00dcr\u00fcn karmas\u0131 probleminin \u00e7oklu dahili ba\u011flama k\u0131s\u0131tlamalar\u0131n\u0131n varl\u0131\u011f\u0131nda \u00e7\u00f6z\u00fcm\u00fc \u00e7ok daha karma\u015f\u0131kt\u0131r ve do\u011frusal programlama olarak bilinen \u00f6zel bir matematiksel tekni\u011fin kullan\u0131lmas\u0131n\u0131 gerektirir.<\/span><\/p>\n

\n

Muhasebe<\/a> Program\u0131<\/span>
\nEn iyi muhasebe program\u0131<\/span>
\nOfis muhasebe programlar\u0131<\/span>
\nMuhasebe programlar\u0131 isimleri<\/span>
\nLogo Muhasebe Program\u0131 \u00f6\u011frenme<\/span>
\nLogo muhasebe program\u0131 Nedir<\/span>
\nLogo muhasebe program\u0131 kullan\u0131m\u0131 pdf<\/span>
\nEn \u00e7ok kullan\u0131lan muhasebe programlar\u0131<\/span><\/p>\n

\n

Do\u011frusal Programlama<\/span><\/strong><\/h3>\n

Do\u011frusal programlama, optimal \u00e7\u00f6z\u00fcm\u00fc bulana kadar olas\u0131 \u00e7\u00f6z\u00fcmler aras\u0131nda arama yapan bir y\u00f6ntemdir. Do\u011frusal programlama teorisi, bir\u00e7ok \u00e7\u00f6z\u00fcm\u00fcn g\u00f6z ard\u0131 edilmesine izin verir. Asl\u0131nda, sonlu say\u0131daki \u00e7\u00f6z\u00fcm d\u0131\u015f\u0131ndaki t\u00fcm \u00e7\u00f6z\u00fcmler teori taraf\u0131ndan elenir ve arama daha sonra elde edilen sonlu k\u00fcme ile s\u0131n\u0131rland\u0131r\u0131l\u0131r.<\/span><\/p>\n

Do\u011frusal programlaman\u0131n, dahili olarak k\u0131s\u0131tlanm\u0131\u015f birden \u00e7ok kaynakla en uygun kar\u0131\u015f\u0131m\u0131 belirlemek i\u00e7in nas\u0131l kullan\u0131labilece\u011fini g\u00f6stermek i\u00e7in Schaller Company \u00f6rne\u011fini kullanmaya devam edece\u011fiz. Bununla birlikte, \u00f6rnek daha geni\u015f \u00e7e\u015fitlilikteki k\u0131s\u0131tlamalar\u0131 i\u00e7erecek \u015fekilde geni\u015fletilecektir. Halihaz\u0131rda tan\u0131mlanan k\u0131s\u0131tlamalara ek olarak, iki dahili k\u0131s\u0131tlama daha eklenecektir.<\/span><\/p>\n

\u0130ki par\u00e7an\u0131n (X ve Y) \u00fc\u00e7 ard\u0131\u015f\u0131k i\u015flemde \u00fcretildi\u011fini varsay\u0131n: ta\u015flama, delme ve cilalama. \u00d6\u011f\u00fctme i\u015flemi, haftada toplam 80 \u00f6\u011f\u00fctme saati sa\u011flayan iki makine kullan\u0131r. Her par\u00e7a bir saat \u00f6\u011f\u00fctme gerektirir. Parlatma i\u015flemi emek yo\u011fundur.<\/span><\/p>\n

Bu i\u015flem haftada 90 \u00e7al\u0131\u015fma saati sa\u011flar. B\u00f6l\u00fcm X, birim ba\u015f\u0131na iki saat kullan\u0131r ve B\u00f6l\u00fcm Y, birim ba\u015f\u0131na bir saat kullan\u0131r. Schaller’in k\u0131s\u0131tlamalar\u0131 hakk\u0131ndaki bilgiler \u00f6zetlenmi\u015ftir. Daha \u00f6nce oldu\u011fu gibi ama\u00e7, Schaller’in kar\u015f\u0131la\u015ft\u0131\u011f\u0131 k\u0131s\u0131tlamalara tabi olarak Schaller’in toplam katk\u0131 pay\u0131n\u0131 maksimize etmektir.<\/span><\/p>\n

Toplam katk\u0131 pay\u0131n\u0131 maksimize etme hedefi matematiksel olarak ifade edilebilir. X, X B\u00f6l\u00fcm\u00fcnde \u00fcretilen ve sat\u0131lan birim say\u0131s\u0131 olsun ve Y, Y B\u00f6l\u00fcm\u00fc olsun. Birim katk\u0131 marjlar\u0131 X ve Y i\u00e7in s\u0131ras\u0131yla 300$ ve 600$ oldu\u011fundan, toplam katk\u0131 pay\u0131 (Z) a\u015fa\u011f\u0131daki gibi ifade edilebilir.\u00a0<\/span><\/p>\n

Schaller’in problemi, Denklemlerdeki k\u0131s\u0131tlamalara tabi olarak toplam katk\u0131 pay\u0131n\u0131 maksimize eden X ve Y birimlerinin say\u0131s\u0131n\u0131 se\u00e7mektir. Bu problem, bir lineer programlama probleminin (genellikle lineer programlama modeli olarak an\u0131l\u0131r) standart form\u00fclasyonu olan a\u015fa\u011f\u0131daki \u015fekilde ifade edilebilir.<\/span><\/p>\n

Son iki k\u0131s\u0131tlama, negatif olmayan k\u0131s\u0131tlamalar olarak adland\u0131r\u0131l\u0131r ve basit\u00e7e, bir \u00fcr\u00fcn\u00fcn negatif miktarlar\u0131n\u0131n \u00fcretilemeyece\u011fi ger\u00e7e\u011fini yans\u0131t\u0131r. T\u00fcm k\u0131s\u0131tlamalar birlikte al\u0131nd\u0131\u011f\u0131nda k\u0131s\u0131tlama seti olarak adland\u0131r\u0131l\u0131r.<\/span><\/p>\n

Uygulanabilir bir \u00e7\u00f6z\u00fcm, do\u011frusal programlama modelindeki k\u0131s\u0131tlamalar\u0131 kar\u015f\u0131layan bir \u00e7\u00f6z\u00fcmd\u00fcr. T\u00fcm olas\u0131 \u00e7\u00f6z\u00fcmlerin toplam\u0131na uygun \u00e7\u00f6z\u00fcm k\u00fcmesi denir. \u00d6rne\u011fin, bir birim K\u0131s\u0131m X ve bir birim K\u0131s\u0131m Y’nin \u00fcretilmesi ve sat\u0131lmas\u0131, uygun bir \u00e7\u00f6z\u00fcm ve uygun k\u00fcmenin bir \u00fcyesi olacakt\u0131r.<\/span><\/p>\n

Bu \u00fcr\u00fcn kar\u0131\u015f\u0131m\u0131 t\u00fcm k\u0131s\u0131tlamalar\u0131 a\u00e7\u0131k\u00e7a kar\u015f\u0131lamaktad\u0131r. Ancak kar\u0131\u015f\u0131m haftada sadece 900 dolar kazanacakt\u0131. Bununla birlikte, bir\u00e7ok uygulanabilir \u00e7\u00f6z\u00fcm daha y\u00fcksek karlar sunar (\u00f6rne\u011fin, her par\u00e7adan iki tane \u00fcretmek). Ama\u00e7 en iyiyi belirlemektir. Toplam katk\u0131 pay\u0131n\u0131 maksimize eden m\u00fcmk\u00fcn olan en iyi \u00e7\u00f6z\u00fcme optimal \u00e7\u00f6z\u00fcm denir.<\/span><\/p>\n

Grafik \u00c7\u00f6z\u00fcm<\/span><\/strong><\/h3>\n

Yaln\u0131zca iki \u00fcr\u00fcn oldu\u011funda, optimal \u00e7\u00f6z\u00fcm grafikle belirlenebilir. Problemi grafikle \u00e7\u00f6zmek, do\u011frusal programlama problemlerinin \u00e7\u00f6z\u00fclme \u015fekline dair \u00f6nemli bir fikir sa\u011flad\u0131\u011f\u0131ndan, Schaller problemi bu \u015fekilde \u00e7\u00f6z\u00fclecektir. Problemin grafiksel olarak \u00e7\u00f6z\u00fcm\u00fcnde d\u00f6rt ad\u0131m izlenir.<\/span><\/p>\n

1. Her k\u0131s\u0131tlaman\u0131n grafi\u011fini \u00e7izin.<\/span>
\n2. Uygulanabilir \u00e7\u00f6z\u00fcm k\u00fcmesini belirleyin.<\/span>
\n3. Uygun k\u00fcmedeki t\u00fcm k\u00f6\u015fe noktas\u0131 de\u011ferlerini tan\u0131mlay\u0131n.<\/span>
\n4. Ama\u00e7 fonksiyonu i\u00e7in en b\u00fcy\u00fck de\u011feri veren k\u00f6\u015fe noktas\u0131n\u0131 se\u00e7in.<\/span><\/p>\n

Schaller \u00f6rne\u011fi i\u00e7in her k\u0131s\u0131tlaman\u0131n grafi\u011fi g\u00f6sterilmektedir. Negatif olmama k\u0131s\u0131tlamalar\u0131 grafi\u011fi ilk \u00e7eyre\u011fe yerle\u015ftirir. Di\u011fer k\u0131s\u0131tlamalar, e\u015fitli\u011fin ge\u00e7erli oldu\u011fu varsay\u0131larak grafiklendirilir. Her k\u0131s\u0131tlama do\u011frusal bir denklem oldu\u011fundan, do\u011fru \u00fczerinde iki nokta belirlenerek, bu noktalar \u00e7izilerek ve birle\u015ftirilerek grafik elde edilir.<\/span><\/p>\n

Her k\u0131s\u0131tlama i\u00e7in uygun bir alan (negatif olmama k\u0131s\u0131tlamalar\u0131 hari\u00e7), sonu\u00e7taki \u00e7izginin alt\u0131nda (veya solunda) bulunan her \u015fey taraf\u0131ndan belirlenir. Uygun k\u00fcme veya b\u00f6lge, her bir k\u0131s\u0131tlaman\u0131n uygulanabilir alan\u0131n\u0131n kesi\u015fimidir. Uygulanabilir k\u00fcme, sergideki ABCD \u015fekli ile g\u00f6sterilmi\u015ftir; \u015feklin s\u0131n\u0131r\u0131n\u0131 i\u00e7erir. Be\u015f k\u0131s\u0131tlamadan sadece ikisinin ba\u011flama k\u0131s\u0131tlamalar\u0131 i\u00e7in aday oldu\u011funa dikkat edin.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Bir Ba\u011flay\u0131c\u0131 \u0130\u00e7 K\u0131s\u0131tlama Her par\u00e7an\u0131n \u00f6zel bir makine taraf\u0131ndan delinmesi gerekti\u011fini varsay\u0131n. Firma, birlikte haftada 120 saat delme sa\u011flayan \u00fc\u00e7 makineye sahiptir. B\u00f6l\u00fcm X, bir saatlik sondaj gerektirir ve B\u00f6l\u00fcm Y, \u00fc\u00e7 saatlik sondaj gerektirir. Ba\u015fka ba\u011flay\u0131c\u0131 k\u0131s\u0131tlamalar olmad\u0131\u011f\u0131 varsay\u0131ld\u0131\u011f\u0131nda, par\u00e7alar\u0131n optimal kar\u0131\u015f\u0131m\u0131 nedir? X B\u00f6l\u00fcm\u00fc’n\u00fcn her birimi bir saat sondaj gerektirdi\u011finden, haftada 120…
Devam\u0131<\/a><\/p>\n","protected":false},"author":6,"featured_media":10303,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[27390,27389,27388],"tags":[27397,27392,27396,27395,27394,27391,23159,27393],"class_list":["post-11082","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-en-cok-kullanilan-muhasebe-programlari","category-en-iyi-muhasebe-programi","category-muhasebe-programi","tag-en-cok-kullanilan-muhasebe-programlari","tag-en-iyi-muhasebe-programi","tag-logo-muhasebe-programi-kullanimi-pdf","tag-logo-muhasebe-programi-nedir","tag-logo-muhasebe-programi-ogrenme","tag-muhasebe-programi","tag-muhasebe-programlari-isimleri","tag-ofis-muhasebe-programlari"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t