{"id":6375,"date":"2021-09-02T14:37:22","date_gmt":"2021-09-02T11:37:22","guid":{"rendered":"https:\/\/bestessayhomework.com\/tr\/?p=6375"},"modified":"2021-09-02T14:37:22","modified_gmt":"2021-09-02T11:37:22","slug":"agirlik-merkezleri-is-sagligi-ve-guvenligi-odevleri-is-sagligi-ve-guvenligi-tez-yaptirma-isg-is-sagligi-ve-guvenligi-tez-yaptirma-ucretleri","status":"publish","type":"post","link":"https:\/\/bestessayhomework.com\/tr\/agirlik-merkezleri-is-sagligi-ve-guvenligi-odevleri-is-sagligi-ve-guvenligi-tez-yaptirma-isg-is-sagligi-ve-guvenligi-tez-yaptirma-ucretleri\/","title":{"rendered":"A\u011f\u0131rl\u0131k Merkezleri  \u2013 \u0130\u015f Sa\u011fl\u0131\u011f\u0131 ve G\u00fcvenli\u011fi \u00d6devleri \u2013 \u0130\u015f Sa\u011fl\u0131\u011f\u0131 ve G\u00fcvenli\u011fi Tez Yapt\u0131rma \u2013 \u0130SG \u2013 \u0130\u015f Sa\u011fl\u0131\u011f\u0131 ve G\u00fcvenli\u011fi Tez Yapt\u0131rma \u00dccretleri"},"content":{"rendered":"<h3 style=\"text-align: center\"><strong><span style=\"color: #99cc00;font-family: 'times new roman', times, serif\">Yakla\u015f\u0131k A\u011f\u0131rl\u0131klar\u0131 Hesaplama<\/span><\/strong><\/h3>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Bir y\u00fck\u00fcn a\u011f\u0131rl\u0131\u011f\u0131 haz\u0131r kaynaklardan elde edilemedi\u011finde, bu t\u00fcr nesnelerin a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kabaca hesaplanmas\u0131 gerekebilir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">D\u00fczlem \u015fekli\u2014E\u011fer nesne basit bir \u015fekle sahipse, k\u00fcbik i\u00e7erikleri (ve a\u011f\u0131rl\u0131\u011f\u0131) makul bir do\u011fruluk derecesi ile hesaplanabilecek bir dizi dikd\u00f6rtgen geometrik \u015fekle b\u00f6l\u00fcnm\u00fc\u015f olarak d\u00fc\u015f\u00fcn\u00fcn. Bu de\u011ferlerin toplam\u0131 toplam a\u011f\u0131rl\u0131\u011f\u0131 verecektir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">\u00d6rne\u011fin: D\u00fczensiz \u015fekle sahip bir &#8220;d\u00fcz plakan\u0131n&#8221; alan\u0131n\u0131 bulmak i\u00e7in, \u015fekli birka\u00e7 \u00fc\u00e7gene b\u00f6lmek i\u00e7in istedi\u011finiz k\u00f6\u015felerden tebe\u015fir \u00e7izgileri \u00e7izin. Her \u00fc\u00e7gen \u015feklin \u00f6l\u00e7\u00fcs\u00fcn\u00fc al\u0131n ve A = 1\u20442 (b \u00d7 h) form\u00fcl\u00fcn\u00fc uygulay\u0131n. \u00dc\u00e7genlerin toplam\u0131 d\u00fczlemin alan\u0131na e\u015fittir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">D\u00fczensiz \u015fekli A, B ve C olmak \u00fczere \u00fc\u00e7 \u00fc\u00e7gene kesin.<\/span><\/p>\n<ul>\n<li style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">A \u00fc\u00e7geninin taban\u0131 30 in\u00e7 ve y\u00fcksekli\u011fi 9 in\u00e7, alan\u0131 30 \u00d7<\/span><span>\u00a0<\/span><span style=\"color: #000000;font-family: 'times new roman', times, serif\">9\/2 = 135 in\u00e7 2<\/span><\/li>\n<li style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">B \u00fc\u00e7geninin taban\u0131 28 in\u00e7 ve y\u00fcksekli\u011fi 8 1\u20442 in\u00e7, alan\u0131 28 \u00d7 8,5\/2 = 119 in\u00e72<\/span><\/li>\n<li style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">C \u00fc\u00e7geninin taban\u0131 15 in\u00e7 ve y\u00fcksekli\u011fi 3 1\u20442 in\u00e7, alan\u0131 15 \u00d7 3.5\/2 = 26.25 in\u00e7.2<\/span><\/li>\n<\/ul>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Plakan\u0131n toplam alan\u0131, bu nedenle, 135 + 119 + 26.25 = 280.25 in\u00e7.2 Plaka 3\/4-in\u00e7 ise. kal\u0131n, plakan\u0131n hacmi 20.25 \u00d7 3\/4 = 210 in\u00e7.3<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Malzeme a\u011f\u0131rl\u0131klar\u0131 tablosundan, \u00e7elik 0.28 lb\/in.2 a\u011f\u0131rl\u0131\u011f\u0131ndad\u0131r, dolay\u0131s\u0131yla plaka a\u011f\u0131rl\u0131klar\u0131 210 \u00d7 0.28 = 59 lb.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Karma\u015f\u0131k kat\u0131 nesneler\u2014beton bir eleman gibi d\u00fczensiz \u015fekilli kat\u0131 bir nesneyi hesaplamak, nesneyi daha k\u00fc\u00e7\u00fck daha basit geometrik \u015fekillere b\u00f6lmekle ve ard\u0131ndan tek tek par\u00e7alar\u0131n hacimlerini belirlemekle ba\u015flar.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">\u00d6rne\u011fin: D\u00fczensiz \u015fekilli bir beton blo\u011fun a\u011f\u0131rl\u0131\u011f\u0131n\u0131 hesaplamak i\u00e7in, \u015fekli dikd\u00f6rtgen \u015feklinde bir A blo\u011funa ve kat\u0131 bir B piramidinin bir kesik (par\u00e7as\u0131) par\u00e7as\u0131na b\u00f6l\u00fcn. A par\u00e7as\u0131n\u0131n hacmi 4 \u00d7 5 \u00d7 3.5 ft = 70 ft3&#8217;t\u00fcr. B b\u00f6l\u00fcm\u00fcn\u00fcn hacmi, t\u00fcm piramidin (6 ft y\u00fcksekli\u011finde) hacminden \u00fcst piramidin (3 ft y\u00fcksekli\u011finde) hacminin \u00e7\u0131kar\u0131lmas\u0131yla bulunur.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">B\u00fcy\u00fck piramidin hacmi, taban\u0131n alan\u0131, \u00e7arp\u0131 y\u00fcksekli\u011finin \u00fc\u00e7te biri 4 \u00d7 5 \u00d7 6\/3 = 40 ft3&#8217;t\u00fcr. Bundan, 2 \u00d7 2 1\u20442 \u00d7 3\/3 = 5 ft3 k\u00fc\u00e7\u00fck piramidin hacmini \u00e7\u0131kar\u0131n. B\u00f6ylece kesi\u011fin hacmi 40 \u2013 5 = 35 ft3&#8217;t\u00fcr. Beton yap\u0131n\u0131n toplam hacmi 70 + 35 = 105 ft3&#8217;t\u00fcr. Beton yakla\u015f\u0131k 144 lb\/ft3 a\u011f\u0131rl\u0131\u011f\u0131nda oldu\u011fundan, blok 105 \u00d7 144 = 15.120 lb veya yakla\u015f\u0131k 7 1\/2 ton a\u011f\u0131rl\u0131\u011f\u0131ndad\u0131r.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Kald\u0131r\u0131lacak \u00e7o\u011fu malzemenin a\u011f\u0131rl\u0131\u011f\u0131, fit k\u00fcp ba\u015f\u0131na a\u011f\u0131rl\u0131klar\u0131na dayand\u0131\u011f\u0131ndan, a\u011f\u0131rl\u0131\u011f\u0131n tahmin edilebilmesi i\u00e7in \u00f6ncelikle ka\u00e7 fit k\u00fcp malzemenin (hacminin) kald\u0131r\u0131lmas\u0131 gerekti\u011fini belirlemek gerekir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Baz\u0131 yayg\u0131n malzemelerin a\u011f\u0131rl\u0131klar\u0131, bir donan\u0131mc\u0131n\u0131n belirli bir y\u00fck\u00fcn yakla\u015f\u0131k a\u011f\u0131rl\u0131\u011f\u0131n\u0131 hesaplamas\u0131n\u0131 sa\u011flamal\u0131d\u0131r. \u015e\u00fcpheye d\u00fc\u015ft\u00fc\u011f\u00fcn\u00fczde, i\u015fteki bir m\u00fchendis veya ustaba\u015f\u0131ndan tavsiye almaktan \u00e7ekinmeyin.<\/span><\/p>\n<p style=\"text-align: center\"><span style=\"color: #008000\">D\u00fczg\u00fcn olmayan <a href=\"https:\/\/bestessayhomework.com\/#team-1\" target=\"_blank\" rel=\"noopener\">cisimlerin<\/a> a\u011f\u0131rl\u0131k merkezleri<\/span><br \/>\n<span style=\"color: #008000\">Statik a\u011f\u0131rl\u0131k merkezi bulma<\/span><br \/>\n<span style=\"color: #008000\">A\u011f\u0131rl\u0131k merkezi nedir<\/span><br \/>\n<span style=\"color: #008000\">A\u011f\u0131rl\u0131k merkezi bulma<\/span><br \/>\n<span style=\"color: #008000\">K\u00fctle merkezi ve a\u011f\u0131rl\u0131k merkezi fark\u0131<\/span><br \/>\n<span style=\"color: #008000\">Dairenin a\u011f\u0131rl\u0131k merkezi<\/span><br \/>\n<span style=\"color: #008000\">A\u011f\u0131rl\u0131k merkezi HESAPLAMA program\u0131<\/span><br \/>\n<span style=\"color: #008000\">V\u00fccut a\u011f\u0131rl\u0131k merkezi nerededir<\/span><\/p>\n<h3 style=\"text-align: center\"><strong><span style=\"color: #99cc00;font-family: 'times new roman', times, serif\">A\u011f\u0131rl\u0131k Merkezlerinin Belirlenmesi<\/span><\/strong><\/h3>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">S\u0131kl\u0131kla, donat\u0131c\u0131, d\u00fczensiz \u015fekilli bir y\u00fck\u00fc kald\u0131rmak i\u00e7in g\u00fcvenli bir \u015fekilde asmadan \u00f6nce a\u011f\u0131rl\u0131k merkezini belirlemelidir. A\u011f\u0131rl\u0131k merkezi teorik olarak cismin t\u00fcm a\u011f\u0131rl\u0131\u011f\u0131n\u0131n merkezinin yo\u011funla\u015ft\u0131\u011f\u0131 ve cismin kald\u0131r\u0131ld\u0131\u011f\u0131nda dengede kalaca\u011f\u0131 konumdur. Nesne bir kancadan serbest\u00e7e as\u0131ld\u0131\u011f\u0131nda, bu nokta her zaman kancan\u0131n alt\u0131na y\u00f6nlendirilecektir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">B\u00f6ylece, a\u011f\u0131rl\u0131k merkezinin \u00fczerinden ve \u00fcst\u00fcnden sarkan bir y\u00fck dengede olacak ve hi\u00e7bir \u015fekilde ask\u0131dan kayma veya dengesizle\u015fme e\u011filiminde olmayacakt\u0131r.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Elbette, kat\u0131 bir \u015feklin a\u011f\u0131rl\u0131k merkezi \u00fc\u00e7 d\u00fczlemde veya y\u00f6nde bulunmal\u0131d\u0131r: uzunlamas\u0131na, \u00e7apraz ve dikey. Kat\u0131 bir \u015feklin a\u011f\u0131rl\u0131k merkezinin tam yerini bulmak matematiksel hesaplamalar gerektirir. Ancak ortalama bir arma i\u015fi i\u00e7in a\u011f\u0131rl\u0131k merkezi yeterince yak\u0131ndan tahmin edilebilir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">\u00d6rne\u011fin: Bir karton par\u00e7as\u0131ndan, uygun herhangi bir \u00f6l\u00e7ekte, tan\u0131d\u0131k ve baz\u0131 d\u00fczensiz \u015fekilli plan \u015fekillerini temsil edecek bir \u015fekil, a\u011f\u0131rl\u0131k merkezlerinin tam yerini belirlemek i\u00e7in bir nesnenin uzunlu\u011funu veya enine kesitini temsil eden bir \u015fekildir.<\/span><\/p>\n<h3 style=\"text-align: center\"><strong><span style=\"color: #99cc00;font-family: 'times new roman', times, serif\">D\u00fczensiz Nesneler<\/span><\/strong><\/h3>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Karton \u015feklin biti\u015fik iki k\u00f6\u015fesine yak\u0131n delikler a\u00e7\u0131n ve ard\u0131ndan duvara veya ba\u015fka bir dikey y\u00fczeye s\u0131k\u0131\u015fm\u0131\u015f bir pimden serbest\u00e7e ask\u0131ya al\u0131n. Bir ipe ba\u011fl\u0131 k\u00fc\u00e7\u00fck bir \u00e7ek\u00fcl veya ba\u015fka bir a\u011f\u0131rl\u0131\u011f\u0131 pimden as\u0131n ve ip boyunca kartona bir \u00e7izgi \u00e7izin; di\u011fer deli\u011fi kullanarak tekrarlay\u0131n. Cismin a\u011f\u0131rl\u0131k merkezi, kald\u0131r\u0131lacak \u015feklin kesi\u015fim noktas\u0131nda yer alacakt\u0131r.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">D\u00fczensiz \u015fekilli bir nesnenin a\u011f\u0131rl\u0131k merkezini belirlemenin bir ba\u015fka yolu, \u015fekli basit k\u00fctlelere b\u00f6lmek, ard\u0131ndan ortaya \u00e7\u0131kan dengeleme y\u00fck\u00fcn\u00fc ve a\u011f\u0131rl\u0131klar\u0131n ilgili kald\u0131ra\u00e7 kollar\u0131yla \u00e7arp\u0131lan a\u011f\u0131rl\u0131klar\u0131n dengelenece\u011fi bir noktada konumunu belirlemektir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">A\u011f\u0131rl\u0131k merkezinin kolayca hesaplanamad\u0131\u011f\u0131 garip \u015fekilli g\u00f6vdelerde, donat\u0131c\u0131 bir a\u011f\u0131rl\u0131k merkezi almal\u0131, ard\u0131ndan deneme yan\u0131lma yoluyla d\u00fczeltmeli, vinci, y\u00fck\u00fc ve ask\u0131 ask\u0131s\u0131n\u0131 bir hareket alana kadar her seferinde biraz hareket ettirmelidir. tatmin edici sonu\u00e7 al\u0131n\u0131r.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Herhangi bir y\u00fck, yerden kald\u0131r\u0131ld\u0131ktan sonra y\u00fczde 5&#8217;ten fazla e\u011filirse, derhal yere indirilmeli ve yeniden donat\u0131lmal\u0131d\u0131r. Do\u011fru konumland\u0131rma i\u00e7in d\u00f6n\u00fc\u015f s\u0131ras\u0131nda y\u00fck\u00fc her zaman a\u011f\u0131rl\u0131k merkezinin \u00fczerinde desteklemek i\u00e7in bir ba\u011flant\u0131 d\u00fczenlenmelidir, b\u00f6ylece y\u00fck kontrol alt\u0131nda olmadan asla d\u00f6nme e\u011filiminde olmaz.<\/span><\/p>\n<h3 style=\"text-align: center\"><strong><span style=\"color: #99cc00;font-family: 'times new roman', times, serif\">G\u00fcvenlik Fakt\u00f6rlerinin Uygulanmas\u0131<\/span><\/strong><\/h3>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Belirli bir y\u00fck\u00fc hareket ettirmek i\u00e7in kullan\u0131lacak halat tipini ve boyutunu se\u00e7meden \u00f6nce a\u011f\u0131rl\u0131k merkezi fakt\u00f6rlerinin dikkate al\u0131nmas\u0131 gerekmesine ra\u011fmen, donat\u0131c\u0131n\u0131n arma ve kald\u0131rma ekipman\u0131n\u0131 etkileyebilecek t\u00fcm de\u011fi\u015fkenleri de\u011ferlendirmesi neredeyse imkans\u0131zd\u0131r. Bu nedenle, \u00f6ng\u00f6r\u00fclemeyen etkileri telafi etmek i\u00e7in kullan\u0131lan malzemeye genellikle bir g\u00fcvenlik fakt\u00f6r\u00fc uygulan\u0131r.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Bu fakt\u00f6r, bir malzemenin ola\u011fan k\u0131r\u0131lma mukavemetinin izin verilen y\u00fck a\u011f\u0131rl\u0131\u011f\u0131na b\u00f6l\u00fcm\u00fc olarak tan\u0131mlan\u0131r. Pulluk \u00e7elik kablo durumunda, fakt\u00f6r 10&#8217;dur; manila ipi i\u00e7in 5&#8217;tir. Bununla birlikte, g\u00fcvenlik fakt\u00f6rleri, bir \u00fcreticinin kullan\u0131m i\u00e7in neyin g\u00fcvenli oldu\u011funa ve dikkate al\u0131nan malzemeye ili\u015fkin deneyimine g\u00f6re de\u011fi\u015febilir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">\u00d6rne\u011fin: Belirli bir 1\/4 in\u00e7 \u00e7ap\u0131nda, pulluk \u00e7eli\u011fi kablosunun kopma mukavemeti 50.000 lb ise, bir donat\u0131c\u0131 b\u00f6yle bir kablonun kald\u0131rmas\u0131 gereken maksimum y\u00fck a\u011f\u0131rl\u0131\u011f\u0131 olarak 10.000 lb kullanabilir, oysa 3\/ 5000 lb kopma mukavemetine sahip 4 in\u00e7 \u00e7ap\u0131nda manila ipi, te\u00e7hizat y\u00fcklemeyi 500 lb ile s\u0131n\u0131rlayabilir.<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"color: #000000;font-family: 'times new roman', times, serif\">Bir\u00e7ok k\u00fcm\u00fclatif etkinin s\u0131kl\u0131kla kar\u015f\u0131la\u015f\u0131ld\u0131\u011f\u0131 kald\u0131rma operasyonlar\u0131nda, bir g\u00fcvenlik fakt\u00f6r\u00fc uygulansa bile bir halattaki ger\u00e7ek gerilme ger\u00e7ek kopma mukavemetine yakla\u015fabilir. Belirli bir halat\u0131n g\u00fcvenli \u00e7al\u0131\u015fma y\u00fck\u00fcn\u00fc belirlemeden \u00f6nce, ip \u00fcreticisinin derecelendirmelerini kontrol edin. \u00dcretici, kopma mukavemeti a\u00e7\u0131s\u0131ndan halat kapasitesi sa\u011fl\u0131yorsa, g\u00fcvenli \u00e7al\u0131\u015fma y\u00fck\u00fcn\u00fc elde etmek i\u00e7in bu de\u011feri g\u00fcvenlik fakt\u00f6r\u00fcne b\u00f6ld\u00fc\u011f\u00fcn\u00fczden emin olun.\u00a0<\/span><span style=\"color: #000000;font-family: 'times new roman', times, serif\">G\u00fcvenlik fakt\u00f6r\u00fcn\u00fc asla yedek g\u00fc\u00e7 olarak d\u00fc\u015f\u00fcnmeyin. Ek kapasite i\u00e7in kullan\u0131lamaz. Ayr\u0131ca, hi\u00e7bir ko\u015fulda asla k\u00fc\u00e7\u00fclt\u00fclmemelidir.<\/span><\/p>\n<p style=\"text-align: justify\">\n","protected":false},"excerpt":{"rendered":"<p>Yakla\u015f\u0131k A\u011f\u0131rl\u0131klar\u0131 Hesaplama Bir y\u00fck\u00fcn a\u011f\u0131rl\u0131\u011f\u0131 haz\u0131r kaynaklardan elde edilemedi\u011finde, bu t\u00fcr nesnelerin a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kabaca hesaplanmas\u0131 gerekebilir. D\u00fczlem \u015fekli\u2014E\u011fer nesne basit bir \u015fekle sahipse, k\u00fcbik i\u00e7erikleri (ve a\u011f\u0131rl\u0131\u011f\u0131) makul bir do\u011fruluk derecesi ile hesaplanabilecek bir dizi dikd\u00f6rtgen geometrik \u015fekle b\u00f6l\u00fcnm\u00fc\u015f olarak d\u00fc\u015f\u00fcn\u00fcn. Bu de\u011ferlerin toplam\u0131 toplam a\u011f\u0131rl\u0131\u011f\u0131 verecektir. \u00d6rne\u011fin: D\u00fczensiz \u015fekle sahip bir &#8220;d\u00fcz plakan\u0131n&#8221;&hellip; <br \/> <a class=\"button small blue\" href=\"https:\/\/bestessayhomework.com\/tr\/agirlik-merkezleri-is-sagligi-ve-guvenligi-odevleri-is-sagligi-ve-guvenligi-tez-yaptirma-isg-is-sagligi-ve-guvenligi-tez-yaptirma-ucretleri\/\">Devam\u0131<\/a><\/p>\n","protected":false},"author":6,"featured_media":6378,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[13522,13523,13524,13521],"tags":[13528,13531,13527,13530,13525,13529,13526,13532],"class_list":["post-6375","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-agirlik-merkezi-hesaplama-programi","category-dairenin-agirlik-merkezi","category-kutle-merkezi-ve-agirlik-merkezi-farki","category-vucut-agirlik-merkezi-nerededir","tag-agirlik-merkezi-bulma","tag-agirlik-merkezi-hesaplama-programi","tag-agirlik-merkezi-nedir","tag-dairenin-agirlik-merkezi","tag-duzgun-olmayan-cisimlerin-agirlik-merkezleri","tag-kutle-merkezi-ve-agirlik-merkezi-farki","tag-statik-agirlik-merkezi-bulma","tag-vucut-agirlik-merkezi-nerededir"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/posts\/6375","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/users\/6"}],"replies":[{"embeddable":true,"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/comments?post=6375"}],"version-history":[{"count":0,"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/posts\/6375\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/media\/6378"}],"wp:attachment":[{"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/media?parent=6375"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/categories?post=6375"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bestessayhomework.com\/tr\/wp-json\/wp\/v2\/tags?post=6375"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}