{"id":8258,"date":"2021-12-28T10:57:30","date_gmt":"2021-12-28T07:57:30","guid":{"rendered":"https:\/\/bestessayhomework.com\/tr\/?p=8258"},"modified":"2021-12-28T10:57:30","modified_gmt":"2021-12-28T07:57:30","slug":"avogadro-yasasi-is-sagligi-ve-guvenligi-tez-yaptirma-isg-is-sagligi-ve-guvenligi-tez-yaptirma-ucretleri","status":"publish","type":"post","link":"https:\/\/bestessayhomework.com\/tr\/avogadro-yasasi-is-sagligi-ve-guvenligi-tez-yaptirma-isg-is-sagligi-ve-guvenligi-tez-yaptirma-ucretleri\/","title":{"rendered":"Avogadro Yasas\u0131 \u2013 \u0130\u015f Sa\u011fl\u0131\u011f\u0131 ve G\u00fcvenli\u011fi Tez Yapt\u0131rma \u2013 \u0130SG \u2013 \u0130\u015f Sa\u011fl\u0131\u011f\u0131 ve G\u00fcvenli\u011fi Tez Yapt\u0131rma \u00dccretleri"},"content":{"rendered":"

Avogadro Yasas\u0131: Miktar ve Hacim Aras\u0131ndaki \u0130li\u015fki<\/span><\/strong><\/h3>\n

Baz\u0131 y\u00f6nlerden Avogadro Yasas\u0131 en sezgisel olan\u0131d\u0131r. Avogadro Yasas\u0131, sabit s\u0131cakl\u0131k ve bas\u0131n\u00e7ta bir gaz\u0131n hacminin, gaz\u0131n mol say\u0131s\u0131 ile do\u011fru orant\u0131l\u0131 oldu\u011funu belirtir. Mant\u0131kl\u0131. Bu odada bir balon doldurdu\u011funuzu hayal edin. S\u0131cakl\u0131k ve bas\u0131n\u00e7 sabittir. Daha fazla gaz ekledik\u00e7e balon geni\u015fleyecektir.\u00a0<\/span><\/p>\n

Bu denklemler “hacim gaz\u0131n mol say\u0131s\u0131yla orant\u0131l\u0131d\u0131r veya hacim gaz\u0131n mol say\u0131s\u0131n\u0131n sabit \u00e7arp\u0131m\u0131na e\u015fittir” \u015feklinde okunur. Dolay\u0131s\u0131yla \u00f6nceki denklemlerde n, gaz\u0131n mol say\u0131s\u0131n\u0131 ifade eder.<\/span><\/p>\n

Avogadro Yasas\u0131 hakk\u0131nda daha az sezgisel olabilecek \u015fey, gaz\u0131n kimli\u011fi ne olursa olsun ili\u015fkinin do\u011fru olmas\u0131d\u0131r. Avogadro, ayn\u0131 s\u0131cakl\u0131k ve bas\u0131n\u00e7ta e\u015fit hacimde gazlar\u0131n e\u015fit say\u0131da molek\u00fcl i\u00e7erdi\u011fini g\u00f6zlemledi.<\/span><\/p>\n

Bu, iki farkl\u0131 gaz\u0131n e\u015fit mollerinin belirli bir s\u0131cakl\u0131k ve bas\u0131n\u00e7ta ayn\u0131 hacmi i\u015fgal edece\u011fi anlam\u0131na gelir. Bas\u0131nc\u0131n 1 atmosfer ve s\u0131cakl\u0131\u011f\u0131n 0\u00b0C oldu\u011fu duruma STP denir. Bu ko\u015fullar alt\u0131nda, her gaz 22.4 L yer kaplar. Gaz\u0131n helyum, oksijen, argon veya klor olmas\u0131 fark etmez. T\u00fcm gazlar, belirli bir s\u0131cakl\u0131k ve bas\u0131n\u00e7 alt\u0131nda ayn\u0131 hacmi kaplar. Farkl\u0131 gazlar farkl\u0131 k\u00fctlelere sahip oldu\u011fundan, t\u00fcm gaz yo\u011funluklar\u0131 ayn\u0131 de\u011fildir. Gaz yo\u011funluklar\u0131 bu b\u00f6l\u00fcmde daha sonra tart\u0131\u015f\u0131lacakt\u0131r.<\/span><\/p>\n

\u0130deal Gaz Denklemi<\/span><\/strong><\/h3>\n

Gaz numunelerinden bahsederken bas\u0131n\u00e7, s\u0131cakl\u0131k, hacim ve gaz\u0131n mol say\u0131s\u0131n\u0131n birbiriyle nas\u0131l ili\u015fkili oldu\u011funu az \u00f6nce \u00f6\u011frendiniz.<\/span><\/p>\n

\u0130deal gaz denklemi, bir gaz\u0131n t\u00fcm \u00f6nemli ko\u015fullar\u0131n\u0131 birbiriyle ili\u015fkilendirir ve \u00f6\u011frencilerin bir avu\u00e7 denklemi ezberleme ihtiyac\u0131n\u0131 ortadan kald\u0131r\u0131r. Ger\u00e7ekten, t\u00fcm ili\u015fkiler bununla \u00f6zetlenebilir. R de\u011feri, bas\u0131n\u00e7 ve hacim i\u00e7in kullan\u0131lan birimlere ba\u011fl\u0131d\u0131r. \u0130deal gaz denkleminin faydal\u0131 olmas\u0131 i\u00e7in s\u0131cakl\u0131klar\u0131n Kelvin cinsinden olmas\u0131 gerekir.<\/span><\/p>\n

Denklem, molek\u00fcller aras\u0131 kuvvetlerin ve tek tek gaz molek\u00fcllerinin hacimlerinin ihmal edilebilir oldu\u011fu gazlar\u0131n kinetik-molek\u00fcler teorisinde belirtilen bir gaz\u0131n t\u00fcm \u00f6zelliklerini varsayar. Bu durumda, ideal gaz denklemi mutlak bir s\u0131f\u0131ra ekstrapolasyon yapacakt\u0131r ve bu nedenle mutlak s\u0131cakl\u0131k \u00f6l\u00e7e\u011fi kullan\u0131lmal\u0131d\u0131r. \u00c7o\u011fu kimyager bas\u0131n\u00e7 i\u00e7in atmosferi, hacim i\u00e7in litreyi ve s\u0131cakl\u0131k i\u00e7in Kelvin’i kullan\u0131r. Bu durumda, R = 0.08206 (L\u00b7atm)\/(mol\u00b7K). Bas\u0131n\u00e7, hacim ve s\u0131cakl\u0131k i\u00e7in alternatif birimler kullan\u0131l\u0131yorsa, R i\u00e7in say\u0131sal de\u011fer de\u011fi\u015febilir.<\/span><\/p>\n

Son olarak, ideal gaz denklemini uygulamadan \u00f6nce s\u0131n\u0131rlamalar\u0131n\u0131 anlamal\u0131s\u0131n\u0131z. \u0130deal gaz denklemi bir ideal gaz\u0131 varsayar; yani, gaz molek\u00fcllerinin, gazlar\u0131n kinetik-molek\u00fcler teorisinde yap\u0131lan t\u00fcm varsay\u0131mlara uydu\u011funu varsayar. Ba\u015fka bir deyi\u015fle, gaz molek\u00fclleri aras\u0131nda g\u00fc\u00e7l\u00fc bir \u00e7ekici ve itici kuvvet bulunmamal\u0131d\u0131r. Bu varsay\u0131m\u0131n kar\u015f\u0131lanmad\u0131\u011f\u0131 durumlarda ideal gaz denklemi, bir gaz\u0131n davran\u0131\u015f\u0131n\u0131 tahmin etmek i\u00e7in \u00e7ok zay\u0131f bir model olacakt\u0131r. Molek\u00fcller aras\u0131 kuvvetler ne zaman ihmal edilemez olur? Bir gaz bir s\u0131v\u0131ya yo\u011fu\u015fmak \u00fczereyken, yani daha d\u00fc\u015f\u00fck s\u0131cakl\u0131klarda ve daha y\u00fcksek bas\u0131n\u00e7larda molek\u00fcller aras\u0131 kuvvetler g\u00f6z ard\u0131 edilemez.<\/span><\/p>\n

\n

Avogadro<\/a> say\u0131s\u0131<\/span>
\nAvogadro say\u0131s\u0131 sembol\u00fc<\/span>
\nDalton yasas\u0131<\/span>
\nAvogadro yasas\u0131 \u00c7\u00d6Z\u00dcML\u00dc sorular<\/span>
\nAvogadro say\u0131s\u0131 ne \u0130\u015fe Yarar<\/span>
\nBoyle Yasas\u0131<\/span>
\nAvogadro kanunu kim buldu<\/span>
\nProust kanunu<\/span><\/p>\n

\n

Teknik not<\/span><\/strong><\/p>\n

Yeterince y\u00fcksek bir bas\u0131nca ula\u015f\u0131ld\u0131\u011f\u0131nda baz\u0131 gazlar s\u0131v\u0131la\u015facakt\u0131r. Bunlar s\u0131v\u0131la\u015ft\u0131r\u0131lm\u0131\u015f s\u0131k\u0131\u015ft\u0131r\u0131lm\u0131\u015f gazlar olarak bilinir. \u00d6rne\u011fin, 70\u00b0F’de klor, 87 psig’lik bir VP’ye sahiptir, bu nedenle d\u0131\u015f bas\u0131n\u00e7 87 psig’ye yakla\u015ft\u0131k\u00e7a klor yo\u011fu\u015fmaya ba\u015flayacakt\u0131r. Gaz yasalar\u0131, VP’lerine yak\u0131n bas\u0131n\u00e7larda s\u0131v\u0131la\u015ft\u0131r\u0131lm\u0131\u015f gazlar i\u00e7in kullan\u0131lamaz. Gaz\u0131n ideal bir gaz gibi davrand\u0131\u011f\u0131 d\u0131\u015f bas\u0131nc\u0131n atmosfer bas\u0131nc\u0131na yak\u0131n olmas\u0131 durumunda kullan\u0131labilirler. Molek\u00fcller Aras\u0131 Etkile\u015fimler ve Fiziksel \u00d6zellikleri Tahmin Etme b\u00f6l\u00fcm\u00fcndeki s\u0131cakl\u0131k, bas\u0131n\u00e7 ve maddenin halleri aras\u0131ndaki ili\u015fkiyi g\u00f6steren faz diyagram\u0131na bak\u0131n.<\/span><\/p>\n

De\u011fi\u015fken \u0130\u00e7eren Hesaplamalar: Cebir<\/span><\/strong><\/h3>\n

Gazlar ve fiziksel \u00f6zellikleriyle ilgili \u00e7ok faydal\u0131 baz\u0131 genellemeleri \u00f6\u011frenmek \u00fczeresiniz. Arkalar\u0131ndaki matemati\u011fi kavrarsan\u0131z, bu kavramlar daha kolay anla\u015f\u0131l\u0131r. Burada sunulan, ren bas\u0131nc\u0131n\u0131, s\u0131cakl\u0131k hacmini ve as aras\u0131ndaki glationship mollerini g\u00f6steren ideal gaz yasas\u0131n\u0131 kullanan problemleri \u00e7\u00f6zmek i\u00e7in gereken cebir becerilerinin k\u0131sa bir incelemesidir.<\/span><\/p>\n

\u0130deal gaz yasas\u0131, PV = nRT, bir\u00e7ok de\u011fi\u015fken i\u00e7erir; Bas\u0131n\u00e7 i\u00e7in P, hacim i\u00e7in V, mol say\u0131s\u0131 i\u00e7in n, ideal gaz sabiti (bilinen) i\u00e7in R ve s\u0131cakl\u0131k i\u00e7in T. En basit problemler, biri hari\u00e7 t\u00fcm de\u011fi\u015fkenlerin de\u011ferlerinin bilindi\u011fi problemlerdir. Bu durumda, problem basit\u00e7e bir cebir problemidir, ancak biraz incelemeye ihtiyac\u0131n\u0131z olabilir. A\u00e7\u0131klay\u0131c\u0131 ama\u00e7lar i\u00e7in \u00f6rnek bir problem kullanal\u0131m.<\/span><\/p>\n

25\u00b0C’de ve 1,1 atm bas\u0131n\u00e7ta hacmi 145 L ise \u015fi\u015firilebilir bir sal\u0131 i\u015fgal eden gaz\u0131n mol say\u0131s\u0131n\u0131 hesaplay\u0131n. Hacim, s\u0131cakl\u0131k ve bas\u0131nc\u0131 bildi\u011finizden (ve her zaman R’yi bildi\u011finizden), bilinmeyen tek \u015fey mol say\u0131s\u0131d\u0131r. Sadece denklemi n i\u00e7in \u00e7\u00f6zmeniz gerekiyor. Cebirde, hesaplamak istedi\u011finiz de\u011ferliyi denklemin bir taraf\u0131nda tek ba\u015f\u0131na alarak izole edersiniz.<\/span><\/p>\n

Saldaki mol say\u0131s\u0131n\u0131 hesaplamak i\u00e7in P, V, R ve T i\u00e7in uygun de\u011ferleri girmeniz yeterlidir. Ancak bunu yapmadan \u00f6nce t\u00fcm de\u011ferlerin uygun birimlerde oldu\u011fundan emin olun. Kimyager R = 0.08206 L\u00b7atm\/mol\u00b7K de\u011ferini R de\u011feri olarak kullanmay\u0131 sever. Kullanmay\u0131 d\u00fc\u015f\u00fcnd\u00fc\u011f\u00fcn\u00fcz R de\u011feri buysa, hacminizin litre, bas\u0131nc\u0131n\u0131z\u0131n atmosfer ve s\u0131cakl\u0131\u011f\u0131n\u0131z Kelvin cinsindendir. Size verilen problemde, matemati\u011fi yapmadan \u00f6nce s\u0131cakl\u0131\u011f\u0131n\u0131z\u0131 Kelvin’e \u00e7evirmeniz gerekir: K = 25\u00b0C + 273 = 298\u00b0K.<\/span><\/p>\n

\u015eimdi matemati\u011fi yapabilirsiniz. Birimlerinizi daima de\u011ferlerinizle birlikte yazmal\u0131s\u0131n\u0131z. Bu, yapabilece\u011finiz hatalar\u0131 yakalaman\u0131za yard\u0131mc\u0131 olacakt\u0131r. E\u011fer matemati\u011fi do\u011fru yap\u0131yorsan\u0131z, size sadece istedi\u011finiz birim, bu durumda mol b\u0131rakacak \u015fekilde birimler d\u00fczg\u00fcn bir \u015fekilde iptal edilmelidir.<\/span><\/p>\n

Gaz Yasalar\u0131 Yeniden \u0130ncelendi<\/span><\/strong><\/p>\n

\u0130deal gaz yasas\u0131n\u0131 elde etmek i\u00e7in bas\u0131n\u00e7 ve hacim (Boyle Yasas\u0131), s\u0131cakl\u0131k ve hacim (Charles Yasas\u0131), mol say\u0131s\u0131 ve hacim (Avogadro Yasas\u0131) aras\u0131ndaki ili\u015fkiler kullan\u0131l\u0131r. O zaman bu egzersizi tersten de yapmak m\u00fcmk\u00fcnd\u00fcr. \u0130deal gaz yasas\u0131nda yer alan herhangi iki de\u011fi\u015fken aras\u0131ndaki ili\u015fkiyi, tam ideal gaz yasas\u0131yla ba\u015flay\u0131p daha sonra sabit oldu\u011funu bildi\u011finiz \u015feyi yal\u0131tarak t\u00fcretebilirsiniz.<\/span><\/p>\n

T\u00fcm bunlar ne anlama geliyor ve sahadayken sizi nas\u0131l etkiliyor? Bir gaz \u00f6rne\u011finin belirli bir \u00f6zelli\u011finin bir ko\u015ful de\u011fi\u015ftik\u00e7e nas\u0131l de\u011fi\u015fti\u011fini tahmin edebiliyorsan\u0131z, \u00e7ok daha iyi kararlar alacaks\u0131n\u0131z. \u00d6rne\u011fin bir gaz\u0131n s\u0131cakl\u0131\u011f\u0131 artt\u0131k\u00e7a hacmi de artar.<\/span><\/p>\n

Ayr\u0131ca, hacmi de\u011fi\u015fmezse, belirli bir gaz miktar\u0131n\u0131n bas\u0131nc\u0131 s\u0131cakl\u0131kla do\u011fru orant\u0131l\u0131d\u0131r. Bir kap gazla doldurulursa ve kap \u00fczerine alev darbesi gelirse, s\u0131cakl\u0131\u011f\u0131 ve dolay\u0131s\u0131yla bas\u0131n\u00e7 y\u00fckselir. Bir noktada, kap ar\u0131zalanacak ve bas\u0131n\u00e7 tahliye cihaz\u0131 yoksa gaz\u0131 serbest b\u0131rakacakt\u0131r.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Avogadro Yasas\u0131: Miktar ve Hacim Aras\u0131ndaki \u0130li\u015fki Baz\u0131 y\u00f6nlerden Avogadro Yasas\u0131 en sezgisel olan\u0131d\u0131r. Avogadro Yasas\u0131, sabit s\u0131cakl\u0131k ve bas\u0131n\u00e7ta bir gaz\u0131n hacminin, gaz\u0131n mol say\u0131s\u0131 ile do\u011fru orant\u0131l\u0131 oldu\u011funu belirtir. Mant\u0131kl\u0131. Bu odada bir balon doldurdu\u011funuzu hayal edin. S\u0131cakl\u0131k ve bas\u0131n\u00e7 sabittir. Daha fazla gaz ekledik\u00e7e balon geni\u015fleyecektir.\u00a0 Bu denklemler “hacim gaz\u0131n mol say\u0131s\u0131yla…
Devam\u0131<\/a><\/p>\n","protected":false},"author":6,"featured_media":7832,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[17930,17927,17929,17928],"tags":[17936,17931,17934,17524,17933,17935,17932,17937],"class_list":["post-8258","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-avogadro-kanunu-kim-buldu","category-avogadro-sayisi","category-avogadro-sayisi-ne-ise-yarar","category-avogadro-yasasi-cozumlu-sorular","tag-avogadro-kanunu-kim-buldu","tag-avogadro-sayisi","tag-avogadro-sayisi-ne-ise-yarar","tag-avogadro-sayisi-sembolu","tag-avogadro-yasasi-cozumlu-sorular","tag-boyle-yasasi","tag-dalton-yasasi","tag-proust-kanunu"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t